The maximum vertical height to which a man can throw a ball is 136 m. The maximum horizontal distance upto which he can throw the same ball is

Answer (2)

Given,

Maximum vertical height,

$\displaystyle H_{max}=\frac{v^2}{2g}=136m$

Maximum range,

$\displaystyle \begin{aligned}R_{max}&=\frac{v^2}{g}=2\times\frac{v^2}{2g}\\&=2\times136=272m \end{aligned}$