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Given,ΔFF×100=4%,ΔLL×100=2%\displaystyle \frac {\Delta F} {F} \times 100=4\%, \frac {\Delta L} {L} \times 100=2\%FΔF×100=4%,LΔL×100=2% Pressure, P=FA=FL2P=\displaystyle \frac {F} {A}=\frac {F} {L^2} P=AF=L2F ΔPP×100=ΔFF×100+2(ΔLL×100)=4+2×2=8%\displaystyle\begin{aligned}\frac {\Delta P} {P} \times 100&=\frac {\Delta F} {F} \times 100+2\left(\frac {\Delta L} {L} \times 100\right)\\&=4+2\times 2=8\%\end{aligned}PΔP×100=FΔF×100+2(LΔL×100)=4+2×2=8%
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