Question:


The displacement of a particle moving along x-axis with respect to time t is x=at+bt2ct3x = at + b t ^ 2 - c t ^ 3. The dimensions of c are

1)
2)
3)
4)
5)

Solution:
Verified

Answer (3)

Given,

x=at+bt2ct3x=at+bt^2-ct^3

[ct3]=[x]\displaystyle \therefore [ct^3]=[x]

[c]=[x][t3]=[L][T3]=[LT3]\displaystyle \Rightarrow [c]=\frac {[x]} {[t^3]} =\frac {[L]} {[T^3]}=[LT^{-3}]