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Given,ΔMM×100=1%,ΔLL×100=1.5%\displaystyle \frac {\Delta M} {M}\times 100=1\%,\frac {\Delta L} {L}\times 100=1.5\%MΔM×100=1%,LΔL×100=1.5% and ΔTT×100=3%\displaystyle \frac {\Delta T} {T}\times 100=3\%TΔT×100=3% Let, X=ML−1T−1X = ML^{-1}T^{-1}X=ML−1T−1 Then, ΔXX×100=(ΔMM+ΔLL+ΔTT)×100=(1+1.5+3)%=5.5%\displaystyle \begin{aligned}\frac {\Delta X} {X}\times 100 &= \left(\frac {\Delta M} {M}+\frac {\Delta L} {L}+\frac {\Delta T} {T}\right)\times 100\\&=(1+1.5+3)\%=5.5\%\end{aligned}XΔX×100=(MΔM+LΔL+TΔT)×100=(1+1.5+3)%=5.5%
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